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Dutulescudenisa17
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13. Calculează.x + y + z, ştiind că:
a) x = -1,15; y = 3,54; z = -1,25;
b) .x = 0,25; y = − 3 supra 2; z = 0, (3);
72;
c) x = -13 supra 18:y=7 supra 72:z=0,(3)
d) x = −2,1(6); y = − 31 supra 18; z = −3,2.

Dau coroana, cu tot cu rezolvare^_^
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Răspuns :

Targoviste44

[tex]\it a)\ \ -1,15+3,54-1,25=3,54-2,40=1,14\\ \\ \\ b)\ \ 0,25-3+0,(3)=\dfrac{^{3)}1}{\ \ 4}-\dfrac{^{12)}3}{\ \ 1}+\dfrac{^{4)}1}{3}=\dfrac{3-36+4}{12}=\dfrac{7-36}{12}=\dfrac{-29}{12}\\ \\ \\ c)\ \ -\dfrac{^{4)}13}{\ \ 18}+\dfrac{7}{72}+\dfrac{^{8)}3}{\ \ 9}=\dfrac{-52+7+24}{72}=\dfrac{31-52}{72}=\dfrac{\ \ -21^{(3}}{72}=-\dfrac{7}{24}[/tex]

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