[tex]\bf \Delta BCD=dreptunghic\ ( \widehat C=90^o)\ \Rightarrow tg(BDC)=\dfrac{BC}{CD} \Rightarrow tg30^o =\dfrac{6}{CD}\Rightarrow \\ \\ \\ \Rightarrow \dfrac{\sqrt3}{3}=\dfrac{6}{CD}\Rightarrow \dfrac{\ \ \not\sqrt3}{\not\sqrt3\cdot\sqrt3}=\dfrac{6}{CD} \Rightarrow \dfrac{1}{\sqrt3}=\dfrac{6}{CD} \Rightarrow CD=6\sqrt3\ m[/tex]
[tex]\it \mathcal{P}=2(L+\ell)=2(6\sqrt3+6)=12(\sqrt3+1)\ m\\ \\ \\ \mathcal{A}=L\cdot \ell=6\sqrt3\cdot6=36\sqrt3\ m^2[/tex]
