Notăm trapezul ABCD, AB||CD, AB>CD.
AD=25cm, BC=40cm, AC=30cm.
[tex]\it \Delta CAB \sim \Delta DCA \Rightarrow \dfrac{AC}{CD}= \dfrac{AB}{AC}= \dfrac{BC}{AD} \Rightarrow \dfrac{30}{CD}= \dfrac{AB}{30}= \dfrac{40}{25}\\ \\ \\ AB= \dfrac{30\cdot40}{25}=48\ cm\\ \\ \\ CD= \dfrac{25\cdot30}{40}=18,75\ cm[/tex]