Răspuns:
m,Na zilnic= niuxA= 66mmolx23mg/mmol= 1518mg
m,Na suplimentar,zilnic= 2300mg-1518mg=782mg
M,NaCl= (23gNa+ 25,5gCl)/mol =58,5g/mol
58,5mgNaCl.........23mgNa
x.............................782mg
x=m= 2gNaCl,zilnic
saptamanal: 2x7g=14gNaCl
Explicație: