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Bunealuiza244
a fost răspuns

introduceți factorii de sub radical:
a. 2√3; 4√5; 6√7; 12√10;
b. 5√5; 12√1; 1450√0​

Răspuns :

Lasmina

a.2radical3=2²rad3=radical12

4radical5=4²rad5=radical80

6radical7=6²rad7=radical252

12radical10=12²rad10=radical1440

b. 5radical5=5²rad5=radical125

12radical1=12•1=12=>12²=144=>12=radical144

1450radical0=1450•0=0=>0²=0=>0=radical0

Triunghiu

Răspuns:

Explicație pas cu pas:

a√b = √a²xb   - formula de introducere a unui factor sub radical

a.

2√3 = √2²x3 = √4x3 = √12

4√5 = √4²x5 = √16x5 = √80

6√7 = √6²x7 = √36x7 = √252

12√10 = √12²x10 = √144x10 = √1440

b.

5√5 = √5²x5 = √25x5 = √125

12√1 = √12²x1 = √144x1 = √144

1450√0​ = √1450²x0 = 0

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