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n = 2030+2x(1+2+3+......+2029) să fie pătrat perfect dau coroana

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Dianageorgiana794

Răspuns:

[tex]n = 2030+2*(1+2+3+......+2029)\\\\1+2+3+......+2029=\frac{2029*2030}{2} \\\\n=2030+2*\frac{2029*2030}{2}\\\\n=2030+2029*2030\\\\n=2030*(2029+1)\\\\n=2030*2030\\\\n=2030^2-p.perfect[/tex]

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