k) 5+ [90+(20-135: ax 3)-54] × 6=251
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1) [6x (12: a +7 x 8): 3-2 x 9] x7+2×39=792
m) 7 [100 x 68: 17-5 x (60 x 6-2x a)]: 20 = 2
n) 135 +5 000: (1 455-455) + ax (40 +4)=272
o) 832 a+ [40+ 8x (100: 5-90: 5)] x 10 = 592



Prin metoda mersului invers