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Efectuati:{(508x2+22x10)-3x[5x9+44:4-(8x3-14:7)x2]}-1200.

Răspuns :

Cristinaioana2
{(1016+220)-3x[45+11-(24-2)x2]}-1200=
[1236-3x(45+11-22x2)]-1200=
[1236-3x(45+11-44)]-1200=
(1236-3x12)-1200=
(1236-36)-1200=
1200-1200=0
Radulrt

{(1016+220)-3x[45+11-(24-2)x2]}-1200=
[1236-3x(45+11-22x2)]-1200=
[1236-3x(45+11-44)]-1200=
(1236-3x12)-1200=
(1236-36)-1200=
1200-1200=0


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