Răspuns :
Răspuns:
[tex]l=10m\\\\L=10*3= > L=30m\\\\P=2(L+l)\\\\P=2(10+30)= > P=80m-perimetrul\\\\80*6-1*6=474m-sarma[/tex]
[tex]\it L > \ell\ de\ 3\ ori \Rightarrow L=3\cdot\ell=3\cdot10=30\ m\\ \\ \\ \mathcal{P}=2(L+\ell)=2(30+10)=2\cdot40=80\ m\\ \\ 80-1=79\ m\ \ (un\ r\hat and\ de\ s\hat arm\breve a)\\ \\ \\ 6\cdot79=474\ m\ \ (lungimea\ total\breve a\ a\ s\hat armei)[/tex]