Răspuns :
[tex]\it a)\ \ \dfrac{3x-1}{2}+\dfrac{7-2x}{3}=\dfrac{1-3x}{4}\bigg|_{\cdot12} \Rightarrow 18x-6+28-8x=3-9x \Rightarrow \\ \\ \\ \Rightarrow 18x-8x+9x=3+6-28 \Rightarrow 19x=-19\bigg|_{:19} \Rightarrow x=-1[/tex]
[tex]\it a)\ \ \dfrac{3x-1}{2}+\dfrac{7-2x}{3}=\dfrac{1-3x}{4}\bigg|_{\cdot12} \Rightarrow 18x-6+28-8x=3-9x \Rightarrow \\ \\ \\ \Rightarrow 18x-8x+9x=3+6-28 \Rightarrow 19x=-19\bigg|_{:19} \Rightarrow x=-1[/tex]