Cred ca ecuatia este:
[tex](4x+1)^2-9(x+6)(x-1)=7(x+3)^2-8[/tex]
[tex]16x^2+8x+1-9(x^2+5x-6)=7(x^2+6x+9)-8[/tex]
[tex]16x^2+8x+1-9x^2-45x+54=7x^2+42x+63-8[/tex] separam termenii ce contin necunoscuta in partea stanga, si dupa ce reducem termenii asemenea, obtinem:
[tex]-79x=0\Rightarrow x=0[/tex]