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Cum rezolv, x patrat -4x+(x-5)+10

Răspuns :

[tex] x^{2} -4x+(x-5)+10=0 \\ x^{2} -4x+x-5=0 \\ x^{2} -3x-5=0 \\ \Delta= b^{2} -4ac=9-4*1*(-5)=9+20=29 \\ x_1= \frac{-b-\sqrt{\Delta}}{2a}= \frac{3- \sqrt{29} }{2} \\ x_2= \frac{-b+\sqrt{\Delta}}{2a}= \frac{3+ \sqrt{29}}{2} [/tex]

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