x |-∞ -2 1 3 +∞
x+2 | --------------------------0++++++++++++++++++++++++++++++
x-1 |-------------------------------------------0+++++++++++++++++++++
x-3 |--------------------------------------------------------------0++++++++++
(x+2)(x-1)(x-3) | ---------------------------0++++++++0-----------------0+++++++++
Concluzie: x∈(-2,1)U(3,+∞).