[tex]\displaystyle 0,1(6)= \frac{16-1}{90} = \frac{15}{90} ^{(5} = \frac{3}{18} ^{(3} = \frac{1}{6} \\ \\ 0,08(3)= \frac{83-8}{900} = \frac{75}{900} ^{(5} = \frac{15}{180} ^{(15} = \frac{1}{12} \\ \\ m_a= \frac{ \frac{1}{6} + \frac{1}{12} }{2} = \frac{ \frac{2}{12}+ \frac{1}{12} }{2} = \frac{ \frac{3}{12} }{2} = \frac{3}{12} :2= \frac{3}{12} \cdot \frac{1}{2} = \frac{3}{24} ^{(3} = \frac{1}{8} [/tex]
