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Adrianafotomod
a fost răspuns

a) (x+1)²-(x+3)²≥(x-1)²-(x-2)²

Ajutorr!! :* :( 

Răspuns :

Razvanw0w
[tex](x+1)^2-(x+3)^2 \geq (x-1)^2 - (x-2)^2\\ x^2+2x+1-x^2-6x-9 \geq x^2-2x+1-x^2+4x-4\\ -4x-8 \geq 2x-3\\ -6x \geq 5 | \cdot (-1)\\ 6x \leq -5 \Rightarrow x \leq - \dfrac{5}{6} \Rightarrow x \in (-\infty,-\dfrac{5}6][/tex]