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Alleteodora
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Daca x+y= - 2[tex] \sqrt{3[/tex] si x^2 -y^2=4[tex] \sqrt{6[/tex],atunci x-y este egal cu??

Răspuns :

[tex]\displaystyle x+y=-2 \sqrt{3} \\ x^2-y^2=4 \sqrt{6} \\ x-y=? \\ x^2-y^2=4 \sqrt{6} \\ (x+y)(x-y)=4 \sqrt{6} \\ -2 \sqrt{3} (x-y)=4 \sqrt{6} \\ x-y=- \frac{4 \sqrt{6} }{2 \sqrt{3} } \\ x-y=-2 \sqrt{2} [/tex]

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