Răspuns:
x ∈ [-3; -2]
Rezolvare:
[tex]x^2+5x+6\leq0\\[/tex]
[tex]x^2+3x+2x+6\leq0\\[/tex]
[tex]x(x+3)+2(x+3)\leq 0\\[/tex]
[tex](x+3)(x+2)\leq0\\[/tex]
[tex]I.\:\left \{ {{x+3\leq0} \atop {x+2\geq0}} \right. \iff\left \{ {{x\leq-3} \atop {x\geq-3}} \right. \implies \O\\[/tex]
[tex]II.\:\left \{ {{x+3\geq0} \atop {x+2\leq0}} \right. \iff\left \{ {{x\geq-3} \atop {x\leq-2}} \right. \implies \bf \boxed{x\in[-3;\:-2]}\\[/tex]
Succes! ❀
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