Răspuns :
Răspuns:
0
Explicație pas cu pas:
pentru ca da lalalalagh hbb gggggggvvvv
[tex]\Big[ {12}^{5} : \Big( {12}^{2} \Big) ^{2} - \Big( {2}^{100} \Big) ^{2} : \Big( {2}^{99} \Big) ^{2} \Big] : {2}^{2} = [/tex]
[tex]\Big( {12}^{5} : {12}^{2 \cdot2} - {2}^{100 \cdot2} : {2}^{99 \cdot2} \Big) : 4= [/tex]
[tex]\Big( {12}^{5} : {12}^{4} - {2}^{200} : {2}^{198} \Big) : 4 = [/tex]
[tex]\Big( {12}^{5 - 4} - {2}^{200 - 198} \Big) : 4 = [/tex]
[tex]\Big(12 - {2}^{2} \Big) : 4 = [/tex]
[tex] \Big( 12 - 4 \Big) : 4 = 8 : 4 = \boldsymbol {2} [/tex]
Am folosit proprietățile puterilor :
[tex] \boldsymbol {\Big( a^{m} \Big) ^{n} = a^{m \cdot n}} [/tex]
[tex] \boldsymbol { a^{m} : a^{n} = a^{m-n} } [/tex]