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PitickRaluka
a fost răspuns

Im poate rezolva si mie un exercitiu de clasa a V in care sa aflati necunoscuta

[48+50x100:(28:a+3x2)-14]x[(50-4x5)+(143-4x6)]=42316

Răspuns :

[tex][48+5000:(28:a+6)-14]*[(50-20)+(143-24)]=42316 \\ 48+5000:(28:a+6)-14]*149=42316 \\ 48+5000:(28:a+6)-14=42316:149 \\ 5000:(28:a+6)=284-48+14 \\ 28:a+6=5000:250 \\ 28:a=20-6 \\ a=28:14 \\ a=2[/tex]

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