Răspuns :
[tex]\bf1.\\ \\ \it \dfrac{^{7)}7}{\ 4}-\dfrac{23}{28}=\dfrac{49-23}{28}=\dfrac{\ 26^{(2}}{28}=\dfrac{13}{14}\\ \\ \\ \bf2.\\ \\\it \dfrac{^{5)}7}{\ \ 6}-\dfrac{^{2)}16}{\ \ 15}=\dfrac{35-32}{30}=\dfrac{\ \ 3^{(3}}{30}=\dfrac{1}{10}[/tex]
[tex]\bf1.\\ \\ \it \dfrac{^{7)}7}{\ 4}-\dfrac{23}{28}=\dfrac{49-23}{28}=\dfrac{\ 26^{(2}}{28}=\dfrac{13}{14}\\ \\ \\ \bf2.\\ \\\it \dfrac{^{5)}7}{\ \ 6}-\dfrac{^{2)}16}{\ \ 15}=\dfrac{35-32}{30}=\dfrac{\ \ 3^{(3}}{30}=\dfrac{1}{10}[/tex]