Răspuns:
Explicație pas cu pas:
[tex]\bf{(^{3)}3-\frac{1}{3} )\times(\frac{3}{8} )^2=(\frac{9-1}{3} )\times(\frac{3}{8} )^2=\frac{8}{3} \times\frac{3^2}{8^2}=\frac{3}{8} }[/tex]
[tex]\bf{(^{3)}\frac{1}{2}+^{2)}\frac{1}{3}-\frac{1}{6}):4+\frac{7}{9} =(\frac{3+2-1}{6} ):4+\frac{7}{9} =\frac{4}{6}\times\frac{1}{4}+\frac{7}{9} =^{9)}\frac{1}{6} +^{6)}\frac{7}{9} = \frac{9+42}{54} =\frac{51}{54}^{(3} =\frac{17}{18} }[/tex]
[tex]\bf{[(\frac{5}{4} )^2]^2:(1\frac{1}{4} )^3-\frac{2}{3} =(\frac{5}{4} )^4:(\frac{5}{4})^3-\frac{2}{3} =^{3)}\frac{5}{4}-^{4)}\frac{2}{3}= \frac{15-8}{12} =\frac{7}{12} }[/tex]
