Răspuns:
[tex](x + 1)(x + 2) = 0 \\ {x}^{2} + 2x + x + 2 = 0 \\ {x}^{2} + 3x + 2 = 0 \\ delta = {b}^{2} - 4ac \\ {3}^{2} - 4 \times 2 =9 - 8 = 1 \\ x1 = \frac{ - 3 + 1}{2} = \frac{ - 2}{2} = - 1 \\ \\ x2 = \frac{ - 3 - 1}{2} = \frac{ - 4}{2} = - 2 [/tex]
=> S= {-1,-2}
