Răspuns:
[tex]1+2+3+...+42=\frac{42*43}{2} =1806:2=903\\\\1+2+3+...+59=\frac{60*30}{2} =900\\\\(3^{903} +2*3^{900} ):29=\\\\(3^{900} (3^3+2)]:29=\\\\(3^{900}*29):29=\\\\3^{900}=(3^3)^{300} =27^{300}[/tex]
