Răspuns :
[tex](2 \sqrt{2} +3 \sqrt{3} )=(2 \sqrt{2} )^2+2 \cdot 2 \sqrt{2} \cdot 3 \sqrt{3} +(3 \sqrt{3} )^2= \\ =8+12 \sqrt{6} +27=35+12 \sqrt{6} [/tex]
[tex](2 \sqrt{2}+3 \sqrt{3})^{2}=(2 \sqrt{2})^{2} +2*2 \sqrt{2}*3 \sqrt{3} +(3 \sqrt{3})^{2} =2*4+12 \sqrt{6}+9*3 = [/tex][tex]=35+12 \sqrt{6} [/tex]