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Fie f: R→R,f(x)=x² + 2x. Calculaţi suma: f(-20) + f(-10)+ƒ(0)+ƒ(10) +ƒ(20).​

Răspuns :

Asociatia33

f(-20) = 400-40 = 360
f(-10) = 100-20 = 80
f(0) = 0
f(10) = 100+20 = 120
f(20) = 400+40 = 440

suma este 1000

Ilovemath74

f:R→R, f(x) = x² + 2x

[tex]f(-20)+f(-10)+f(0)+f(10)+f(20)=\\=(-20)^2+2\times(-20)+(-10)^2+2\times(-10)+0^2+2\times0+10^2+2\times10+20^2+2\times20=\\=400-40+100-20+0+0+100+20+400+40=\\=\bf1000\\[/tex]

Succes! ❀

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