Răspuns :
Răspuns:
b) [tex]x_{1} = \frac{\sqrt{2} }{2}[/tex] [tex]x_{2} = -\frac{\sqrt{2} }{2}[/tex]
c) [tex]x = 0[/tex]
Explicație pas cu pas:
b)
[tex]x^{2} = \frac{1}{2} = > x_{1} = \frac{1}{\sqrt{2} } = \frac{\sqrt{2} }{2} ; x_{2} = -\frac{\sqrt{2} }{2}[/tex]
c)
[tex]2x^{2} = 0 = > x^{2} = 0 = > x = 0[/tex]
[tex]b) \ x^2 = \dfrac{1}{2} \implies |x | = \pm \sqrt{\dfrac{1}{2}} = \pm \dfrac{\sqrt{2} }{2}[/tex]
[tex]S = \bigg\{-\dfrac{\sqrt{2} }{2};\dfrac{\sqrt{2} }{2}\bigg\}[/tex]
------
[tex]c) \ 2 \cdot x^2 = 0 \implies x^2 = 0 \implies x = 0[/tex]
[tex]S = \{0\}[/tex]