Răspuns:
[tex]a.3^{7+4} =3^{11} \\\\b.2^{6+4+1} =2^{11} \\\\c.7^{8+6} =7^{14} \\\\d.11^{53+47}=11^{100} \\\\e.2^{5x} \\\\f.13^{5a+5b} =13^{5(a+b)} \\\\g.5^{62+37+1} =5^{100} \\\\h.7^{1+2+3+..+100} =7^{5050} \\\\1+2+3+..+100=\frac{100*101}{2}[/tex]
