Explicație pas cu pas:
[tex]a = \sqrt{72} - \sqrt{32} + \sqrt{98} - \sqrt{18} - \sqrt{8} \\ a = 6 \sqrt{2} - 4 \sqrt{2} + 7 \sqrt{2} - 3 \sqrt{2} - 2 \sqrt{2} \\ a = 2 \sqrt{2} + 7 \sqrt{2} - 3 \sqrt{2} - 2 \sqrt{2} \\ a = \: 9 \sqrt{2} - 3 \sqrt{2} - 2 \sqrt{2} \\ a = 6 \sqrt{2} - 2 \sqrt{2} \\ a = 4 \sqrt{2} \\ \\ b = \sqrt{147} - \sqrt{108} + \sqrt{75} - \sqrt{48} + \sqrt{12} \\ b = 7 \sqrt{3 } - 6 \sqrt{3} + 5 \sqrt{3} - 4 \sqrt{3} + 2 \sqrt{3} \\ b = \sqrt{3} + 5 \sqrt{3} - 4 \sqrt{3} + 2 \sqrt{3} \\ b = 6 \sqrt{3} - 4 \sqrt{3} + 2 \sqrt{3} \\ b = 2 \sqrt{3} + 2 \sqrt{3} \\ b = 4 \sqrt{3} \\ \\ a \times b = 4 \sqrt{2} \times 4 \sqrt{3} = 16 \sqrt{6} \\ \frac{a}{b} = \frac{4 \sqrt{2} }{4 \sqrt{3} } = \sqrt{0.(6)} [/tex]
Succes!