Răspuns :
Explicație pas cu pas:
[tex] \sqrt{6} - \sqrt{6} + 2 + 2 \sqrt{3 } \\ = 0 + 2 + 2 \sqrt{3} = 2 + 2 \sqrt{3} = 2(1 + \sqrt{3} )[/tex]
[tex] 0,5 \sqrt{24} -\sqrt{3} \cdot \sqrt{2} +2 +\sqrt{54} : 3\sqrt{2} \\ = 0,5 \cdot 2\sqrt{6} -\sqrt{3\cdot2}+2 +3\sqrt{6} : 3\sqrt{2} \\ =\sqrt{6} -\sqrt{6} +2 +\sqrt{6\cdot2} \\ = 2+\sqrt{12} \\ = 2+2\sqrt{3} \\ \tt = 2(1+\sqrt{3} [/tex]