Răspuns :
x=5
y+z= 14
a) x+2y+2z = x+2(y+z)=5+2*14=5+28=33
b) 5x+3y+ 3z=5x+3(y+z)=5*5+3*14=25+42=67
y+z= 14
a) x+2y+2z = x+2(y+z)=5+2*14=5+28=33
b) 5x+3y+ 3z=5x+3(y+z)=5*5+3*14=25+42=67
[tex]x=5 \\ y+z=14 \\ a).x+2y+2z=x+2(y+z)=5+2 \cdot 14=5+28=33 \\ b).5x+3y+3z=5x+3(y+z)=5 \cdot 5+3 \cdot 14=25+42=67[/tex]