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a fost răspuns

[(1,1/3)la puterea -1. -2 la puterea -2] totul la -3...va rogurgent!!!

Răspuns :

Renatemambouko
[1,1(3)⁻¹-2⁻²]⁻³=
=[(113-11/90)⁻¹-1/2²]⁻³=
=[(112/90)⁻¹-1/2²]⁻³=
=[90/112-1/4]⁻³=
=[45/56-1/4]⁻³=
=[(45-15)/56]⁻³=
=(30/56)⁻³=
=(56/30)³
=(28/15)³
=21952/3375=6,504(296)