Răspuns :
daca m =1 /2
2 · 1 /2 · x = x + 4·1 /2 -2
↓ ↓
2 /2 = 1 4 /2 = 2
x = x + 2 - 2
x = x ; ecutia are o infinitate de solutii , orice x∈ R
2 · 1 /2 · x = x + 4·1 /2 -2
↓ ↓
2 /2 = 1 4 /2 = 2
x = x + 2 - 2
x = x ; ecutia are o infinitate de solutii , orice x∈ R