Răspuns :
Aria in primul caz:[tex]2*3=6cm[/tex]
Perimetrul in primul caz:[tex]2*2+3*2=4+6\\ ~~~~~~~~~~~~~~~~=10cm[/tex]
Aria in al-II-lea caz:[tex]3*10=30cm[/tex]
Perimetrul in al-II-lea caz:[tex]3*2+10*2=6+20\\ ~~~~~~~~~~~~~~~~~~=26cm[/tex]
Aria in al-III-lea caz:[tex]12*1,2=14,4cm[/tex]
Perimetrul in al-III-lea caz:[tex]12*2+1,2*2=24+2,4\\ ~~~~~~~~~~~~~~~~~~~~=26,4cm[/tex]
Perimetrul in primul caz:[tex]2*2+3*2=4+6\\ ~~~~~~~~~~~~~~~~=10cm[/tex]
Aria in al-II-lea caz:[tex]3*10=30cm[/tex]
Perimetrul in al-II-lea caz:[tex]3*2+10*2=6+20\\ ~~~~~~~~~~~~~~~~~~=26cm[/tex]
Aria in al-III-lea caz:[tex]12*1,2=14,4cm[/tex]
Perimetrul in al-III-lea caz:[tex]12*2+1,2*2=24+2,4\\ ~~~~~~~~~~~~~~~~~~~~=26,4cm[/tex]
a) P = 2 * 2 + 2 * 3 = 10 cm
A = 2 * 3 = 6 cm²
b) P = 2 * 3 + 2 * 10 = 26 m
A = 3 * 10 = 30 m²
c) P = 2 * 12 + 2 * 1,2 = 26,4 cm
A = 12 * 1,2 = 14,4 cm²
A = 2 * 3 = 6 cm²
b) P = 2 * 3 + 2 * 10 = 26 m
A = 3 * 10 = 30 m²
c) P = 2 * 12 + 2 * 1,2 = 26,4 cm
A = 12 * 1,2 = 14,4 cm²