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Alyastoian
a fost răspuns

Calculeaza: a) 3x3+3x[3+3x(15-3):3]=? b)2+5x7+2010:30+(4239+761):5000-5=? c)28-3x2+125:5+(32:4-50:10)x4+2=? d)11+3x[2+3x(2x3-5)]-14=? e)4+4:[12-4:4x(16-8)+(3+3)x0]=? f)19+81:[(624:6:4-322:7:2)+3x(148-73x2)]=?

Răspuns :

Anytatha
a) 3x3+3x[3+3x(15-3):3]= 9+3x(3+3x12:3)=9+3x12=9+36=45 
b) 2+5x7+2010:30+(4239+761):5000-5= 2+35+67+5000:5000-5= 100 
c) 28-3x2+125:5+(32:4-50:10)x4+2= 28-6+25+3x4+2=61 
d) 11+3x[2+3x(2x3-5)]-14= 11+3x(2+3x1)-14=11+3x5-14=11+15-14=12
e)4+4:[12-4:4x(16-8)+(3+3)x0]=4+4:(12-1x8+6x0)=4+4:4=5 
 f)19+81:[(624:6:4-322:7:2)+3x(148-73x2)]=19+81:(3+3x2)=19+81:9=27 
Sper ca te-am ajutat!Coronita?

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