[tex]( x-2) ( x+1) \leq 3( x+1) \\ \\ x^{2} +x-2x-2 \leq 3x+3 \\ \\ x^{2} +x-2x-3x \leq 3+2 \\ \\ x^{2} -4x \leq 5 \\ \\ [tex] x^{2} -4x-5 \leq 0 \\ \\ x^{2} -5x+x-5 \leq 0 \\ \\ x(x+1)-5(x+1) \leq 0 \\ \\ (x-5)(x+1) \leq 0 \\ \\ x-5 \leq 0=\ \textgreater \ x=5 \\ \\ x+1 \leq 0=\ \textgreater \ x=-1[/tex]
