[tex] \frac{2}{3} + \frac{x+1}{2}=5- \frac{4-x}{6} [/tex]
[tex] \frac{x+1}{2}+ \frac{4-x}{6} =5- \frac{2}{3} [/tex]
[tex]\frac{3(x+1)}{6}+ \frac{4-x}{6} = \frac{15}{3} - \frac{2}{3}[/tex]
[tex]\frac{3x+3+4-x}{6}= \frac{13}{3}[/tex]
[tex]2x+7= \frac{13*6}{3}[/tex]
2x+7= 26
