Răspuns :
[tex]( \sqrt{3} + \sqrt{6} )^2-( \sqrt{2} - \sqrt{3} )^2= \\ = \sqrt{3} ^2+2 \cdot \sqrt{3} \cdot \sqrt{6} + \sqrt{6} ^2-( \sqrt{2}^2 -2 \cdot \sqrt{2} \cdot \sqrt{3} + \sqrt{3} ^2)= \\ =3+2 \sqrt{18} +6-(2-2 \sqrt{6} +3)=3+6 \sqrt{2} +6-2+2 \sqrt{6} -3= \\ =4+6 \sqrt{2} +2 \sqrt{6} [/tex]