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a fost răspuns

"(√3+√6) la puterea a 2-(√2-√3) la puterea a 2

Răspuns :

(√3+√6)²-(√2-√3)²= 3+2√18+6-2+2√6-3= 2*3√2+4+2√6= 6√2+4+2√6=4+2√2(3+√3)
[tex]( \sqrt{3} + \sqrt{6} )^2-( \sqrt{2} - \sqrt{3} )^2= \\ = \sqrt{3} ^2+2 \cdot \sqrt{3} \cdot \sqrt{6} + \sqrt{6} ^2-( \sqrt{2}^2 -2 \cdot \sqrt{2} \cdot \sqrt{3} + \sqrt{3} ^2)= \\ =3+2 \sqrt{18} +6-(2-2 \sqrt{6} +3)=3+6 \sqrt{2} +6-2+2 \sqrt{6} -3= \\ =4+6 \sqrt{2} +2 \sqrt{6} [/tex]