[tex]log^2_{0,3}x - 5log_{0,3}x + 6 = 0[/tex]
[tex]\text { Notam } log_{0,3}x= t \\ t^2-5t+6=0 \\ \Delta = 25-24 = 1 \\ t_{1,2}= \frac{5 \pm1}{2} \\ t_1 = 3 =\ \textgreater \ log_{0,3}x=3 =\ \textgreater \ x = (0,3)^3= (\frac{3}{10})^3= \frac{27}{1000}=0,027 \\ t_2 = 2 =\ \textgreater \ log_{0,3}x=2 =\ \textgreater \ x = (0,3)^2 = (\frac{3}{10})^2= \frac{9}{100}=0,09[/tex]
