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Delia2001
a fost răspuns

Calculati : a) √2a+√2x b) 4x+4xy c) 3a+3b+3c d) 4x+12y-6z

Răspuns :

[tex]a). \sqrt{2} a+ \sqrt{2} x= \sqrt{2} (a+x) \\ b).4x+4xy=4x(1+y) \\ c).3a+3b+3c=3(a+b+c) \\ d).4x+12y-6z=2(2x+6y-3z)[/tex]

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