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a fost răspuns

a)efectuati impartirea lui (24²+2·13+7)la (3⁴+56⁰-225÷15)
b)aratati ca nr 9·(5+10+15+....+200)÷41 este patrat perfect
c)729÷3³+180/4+(42/3+12¹)/2 ::(34/17)²-2013⁰ :(23-3²-23⁰)²-13²
d)se considera nr naturale a=8si b=3 calculati: a²-b² ,(a+b)² ,a²+2ab+b² ,(a-b)² ,a²-2ab+b²

Răspuns :

Andreemaryyy
a) (576+26+7)= 609
    (81+1-15)=82-15=67
 609:67= 9,08
b) 9x5x(1+2+3+...+40):41=
45X 40X41/2:41=
45X20X41:41=
45x20=
900=30x30=30²
d) a²-b²= (a-b)(a+b)= (8-3)(8+3)= 5x11=55
    a²+2ab+b²= (a+b)²=(8+3)²=11²=121
    a²-2ab+b²= (a-b)²= (8-3)²= 5²= 25

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