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3.Sa se calculeze:
a)[tex]2 \sqrt{8} [/tex]+[tex]2 \sqrt{8}+5 \sqrt{32} + 4 \sqrt{2}=[/tex]
b)[tex]6 \sqrt{3}-2 \sqrt{27}+5 \sqrt{6}: \sqrt{2} [/tex]=
c)[tex] \sqrt{20}-12 \sqrt{5}+ \sqrt{45} =[/tex]=
d)[tex]5 \sqrt{18}+ \sqrt{12}-3 \sqrt{20}+ \sqrt{72}+ \sqrt{45} [/tex]=
e)[tex]3( \sqrt{20}+ \sqrt{45})- \sqrt{125}= [/tex]
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Răspuns :

[tex]a).2 \sqrt{8}+2 \sqrt{8} +5 \sqrt{32} +4 \sqrt{2} =4 \sqrt{2} +4 \sqrt{2} +20 \sqrt{2} +4 \sqrt{2} =32 \sqrt{2} \\ b).6 \sqrt{3} -2 \sqrt{27} +5 \sqrt{6} : \sqrt{2} =6 \sqrt{3} -6 \sqrt{3} +5 \sqrt{3} =5 \sqrt{3} \\ c). \sqrt{20} -12 \sqrt{5} + \sqrt{45} =2 \sqrt{5} -12 \sqrt{5} +3 \sqrt{5} =-7 \sqrt{5} [/tex]
[tex]d).5 \sqrt{18} + \sqrt{12} -3 \sqrt{20} + \sqrt{72} + \sqrt{45} = \\ =15 \sqrt{2} +2 \sqrt{3} -6 \sqrt{5} +6 \sqrt{2} +3 \sqrt{5} =21 \sqrt{2} +2 \sqrt{3} -3 \sqrt{5} \\ e).3( \sqrt{20} + \sqrt{45} )- \sqrt{125} =3(2 \sqrt{5} +3 \sqrt{5} )-5 \sqrt{5} = \\ =3 \cdot 5 \sqrt{5} -5 \sqrt{5} =15 \sqrt{5} -5 \sqrt{5} =10 \sqrt{5} [/tex]

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