Trapezul ABCD are AB↑↑(paralel)CD,AB=15cm,CD=18cm,AD=8cm si BC=10cm.Daca AD ⊃BC=E in alcolada,calculati perimetrul triunghiului EAB
va rog,imi trebuie urgent!!!
AB II BC teorema lui Thales EA/ED=EB/EC=AB/DC x/(x+8)=y/(y+10)=15/18 x/(x+8)=15/18 ⇒18x=15x+120 ⇒3x=120 ⇒EA=x=40 y/(y+10)=15/18 ⇒18y=15y+150 ⇒3x=150 ⇒EB=y=50
ED=40+8=48 cm EC=50+10=60 cm DC=18 cm P=48+60+18=116 cm