a) |x+1| = 2
Avem 2 ramuri:
x+1=2 sau x+1=-2
x=1 x=-3
S={-3,1}
b) |x+4|=x-3
x+4=x-3 sau x+4=-x+3
0=-7 fals 2x=-1
x=[tex] \frac{-1}{2} [/tex]
S={[tex] \frac{-1}{2} [/tex]}
c) 2x<3x+6
-6<3x-2x
-6<x
x>-6
S={-5,-4,-3,-2,-1,0,1,2,3,...}
d) 3-2x>7x-2
3+2>7x+2x
5>9x
9x<5
x<[tex] \frac{5}{9} [/tex]
S={...-2,-1,0}
Imi votezi ca cel mai bun raspuns? :D
