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[tex]a)2 \sqrt{18} +3 \sqrt{8}+3 \sqrt{32}- \sqrt{50.}------b)(3 \sqrt{5}-2)(3 \sqrt{5}-1) [/tex]

Răspuns :

Flavistin
[tex]a) \\ 2 \sqrt{18}+3\sqrt{8}+3\sqrt{32}-\sqrt{50}= \\ \sqrt{72}+\sqrt{72}+\sqrt{288}-\sqrt{50}= \\ \sqrt{722}= \\ \sqrt{2*19^{2}} = \\ 19\sqrt{2}=26,87005...[/tex]
[tex]b) \\ (3\sqrt{5}-2)*(3\sqrt{5}-1)=(\sqrt{45}-2)*(\sqrt{45}-1)[/tex]