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3246-{aa:a+[(m+bbb:b)-777:7]x7+ 333-55:5}x3=2016
gasiti numerele impare consecutive in ordinea urmatoare m, a, b

Răspuns :

Renatemambouko
3246-{aa:a+[(m+bbb:b)-777:7]x7+ 333-55:5}x3=2016
-{11+[(m+111-111]x7+ 333-11}x3=2016-3246
(11+mx7+ 333-11)x3=1230
mx7+ 333=410
mx7=77
m=11
a=11+2=13
b=13+2=15

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