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Raportul masurilor a doua unghiuri suplementare este de 7 supra 11. Determinati masurile lot.

Răspuns :

Renatemambouko
a+b=180⁰
a/b=7/11
11a=7b
b=11a/7
a+11a/7=180⁰
7a+11a=1260⁰
18a=1260⁰
a=70⁰
b=180-70=110⁰
Morwanneg
m(A) / m(B) = 7/11.
7 m(B) = 11 m(A)
m(B)= 11m(A) / 7
m(B) + m(A) = 180
11m(A) / 7  + m(A) = 180
11m(A) / 7 + 7 m(A) / 7= 1260 / 7
11 m(A) + 7 m(A)= 1260
18 m(A)= 1260
m(A)= 1260 / 18
m(A) = 70
m(B)= 180-70=110.

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