Răspuns :
[tex] \sqrt{3} +2 \sqrt{27} - \sqrt{75} = \sqrt{3} +2 \cdot 3 \sqrt{3} -5 \sqrt{3} = \sqrt{3} +6 \sqrt{3} -5 \sqrt{3} = \\ =7 \sqrt{3} -5 \sqrt{3} =2 \sqrt{3} [/tex]
[tex] \sqrt{3} + 2 \sqrt{27} - \sqrt{75} = \\ =\sqrt{3} + 2 \sqrt{3^3} - \sqrt{5^2\cdot3} = \\= \sqrt{3} + 2 \sqrt{3}\cdot \sqrt{3^2} - \sqrt{5^2}\cdot \sqrt{3} = \\ =\sqrt{3} + 6 \sqrt{3} - 5\sqrt{3} = \\ =7 \sqrt{3} -5 \sqrt{3} =\\ = 2 \sqrt{3} [/tex]