1 / ( x + 2y + 3z ) = xy / 100
x , y = 0 ,1,2,.. , 9 in baza zece
1 / ( x +2y + 3z ) = ( 10x + y ) /100 ; modificam proportia
100 = 10 · 10
⇒ 10 / ( x + 2y + 3z ) = ( 10x + y ) / 10
egalam numaratorii , numitorii
10 = 10x + y daca y = 0 ; 10 =10x ; x =1
x + 2y + 3z = 10 1 + 2·0 +3z = 10 ; 3z = 10 -1
3z = 9 ; z = 3