👤
a fost răspuns

Calculati:
a)5 la puterea 2+25 la puterea 0-3*10
b)6 la puterea 3*5+6*5 la puterea 3-5*6=
c)32*4-4*32+17*3 la puterea 2=
d)12 la puterea 2:48/48:24+2 la puterea 6=
e)99-4 la puterea 3+625:5 la puterea 2-17*2013 la puterea 0=
Va rog repede!!

Răspuns :

[tex] \displaystyle a).5^2+25^0-3 \cdot 10=25+1-30=26-30=-4 \\ \\ b).6^3 \cdot 5 +6 \cdot 5 ^3-5 \cdot 6=216 \cdot 5 +6 \cdot 125-30=1080+750-30= \\ \\ =1830-30=1800 \\ \\ c).32 \cdot 4-4 \cdot 32+17 \cdot 3^2=128-128+17 \cdot 9=153 \\ \\ d).12^2: \frac{48}{48} :24+2^6=144:1:24+64=144:24+64=6+64=70 \\ \\ e).99-4^3+625:5^2-17 \cdot 2013^0=99-64+625:25-17 \cdot 1= \\ \\ =35+25-17=60-17=43[/tex]

Alte intrebari