Răspuns :
10≤x≤20;
⇒10/3=3[rest 1];
⇒20/3=6[rest 2];
⇒1+2+1+2+1+2+1+2=3·4=12⇒suma resturilor impartirilor tuturor numerelor naturale x la numarul 3;
⇒10/3=3[rest 1];
⇒20/3=6[rest 2];
⇒1+2+1+2+1+2+1+2=3·4=12⇒suma resturilor impartirilor tuturor numerelor naturale x la numarul 3;
10:x=3 rest 1
11:x=3 rest 2
12:x=4 rest 0
13:x=4 rest 1
14:x=4 rest 2
15:x=5 rest 0
16:x=5 rest 1
17:x=5 rest 2
18:x=6 rest 0
19:x=6 rest 1
20:x=6 rest 2
Suma resturilor:1+2+0+1+2+0+1+2+0+1+2=12